Read two integers a and b and print both ways of dividing them: plain truncating integer division on the
first line, and the real (non-truncating) division, rounded to 2 decimal places, on the second.
The first line is just a / b – both operands are already int, so it truncates on its own. The second line is
the one to be deliberate about: a / b alone would still compute the truncated integer result first and only
convert it to a double afterward, by which point the remainder is already gone. You need a cast on at least one
operand – (double)a / b – to make the division itself happen in floating point, exactly as covered at the end
of the lesson.